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๋ชฉ๋กํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค 42586 (1)

๐‘†๐‘ข๐‘›๐‘ โ„Ž๐‘–๐‘›๐‘’ ๐‘Ž๐‘“๐‘ก๐‘’๐‘Ÿ ๐‘Ÿ๐‘Ž๐‘–๐‘›โœง

[ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค] 42586๋ฒˆ ๊ธฐ๋Šฅ๊ฐœ๋ฐœ

ํ”„๋กœ์ ํŠธ๋ฅผ ๋๋‚ด๊ณ  ์˜ค๋žœ๋งŒ์— ์Šคํ„ฐ๋””์—์„œ ํ’€๊ธฐ๋กœ ํ•œ ์•Œ๊ณ ๋ฆฌ์ฆ˜ ๋ฌธ์ œ๋ฅผ ์‹œ๋„ํ•ด๋ดค์Šต๋‹ˆ๋‹น ์ž๊พธ ์‹คํŒจํ•ด์„œ ๊ตฌ๊ธ€๋ง ํ•˜๊ณ  ์‹ถ์—ˆ์ง€๋งŒ... ๊พน ์ฐธ๊ตฌ์„œ ํ’€์—ˆ๋”๋‹ˆ ๊ฒฐ๊ตญ 3์‹œ๊ฐ„๋งŒ์— ํ’€์—‡์Šต๋‹ˆ๋‹ค!!ใ…Žใ…Ž ์•„์ฃผ ๋ฟŒ๋“ฏ^_____________^ ๋ฌธ์ œ: https://school.programmers.co.kr/learn/courses/30/lessons/42586 def solution(progresses, speeds): for i in range(len(progresses)): a = 100 - progresses[i] if a % speeds[i] != 0: progresses[i] = (a // speeds[i]) + 1 else: progresses[i] = a // speeds[i] result = [] count = 1 st..
๐—ฃ๐—ฟ๐—ผ๐—ด๐—ฟ๐—ฎ๐—บ๐—บ๐—ถ๐—ป๐—ด๐Ÿ’ป/[๐๐ฒ๐ญ๐ก๐จ๐ง] ๐€๐ฅ๐ ๐จ๐ซ๐ข๐ญ๐ก๐ฆ 2022. 11. 16. 03:29
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